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- """
- pytts voice service (offline)
- """
-
- import os
- import sys
- import time
-
- import pyttsx3
-
- from bridge.reply import Reply, ReplyType
- from common.log import logger
- from common.tmp_dir import TmpDir
- from voice.voice import Voice
-
-
- class PyttsVoice(Voice):
- engine = pyttsx3.init()
-
- def __init__(self):
- # 语速
- self.engine.setProperty("rate", 125)
- # 音量
- self.engine.setProperty("volume", 1.0)
- if sys.platform == "win32":
- for voice in self.engine.getProperty("voices"):
- if "Chinese" in voice.name:
- self.engine.setProperty("voice", voice.id)
- else:
- self.engine.setProperty("voice", "zh")
- # If the problem of espeak is fixed, using runAndWait() and remove this startLoop()
- # TODO: check if this is work on win32
- self.engine.startLoop(useDriverLoop=False)
-
- def textToVoice(self, text):
- try:
- # Avoid the same filename under multithreading
- wavFileName = "reply-" + str(int(time.time())) + "-" + str(hash(text) & 0x7FFFFFFF) + ".wav"
- wavFile = TmpDir().path() + wavFileName
- logger.info("[Pytts] textToVoice text={} voice file name={}".format(text, wavFile))
-
- self.engine.save_to_file(text, wavFile)
-
- if sys.platform == "win32":
- self.engine.runAndWait()
- else:
- # In ubuntu, runAndWait do not really wait until the file created.
- # It will return once the task queue is empty, but the task is still running in coroutine.
- # And if you call runAndWait() and time.sleep() twice, it will stuck, so do not use this.
- # If you want to fix this, add self._proxy.setBusy(True) in line 127 in espeak.py, at the beginning of the function save_to_file.
- # self.engine.runAndWait()
-
- # Before espeak fix this problem, we iterate the generator and control the waiting by ourself.
- # But this is not the canonical way to use it, for example if the file already exists it also cannot wait.
- self.engine.iterate()
- while self.engine.isBusy() or wavFileName not in os.listdir(TmpDir().path()):
- time.sleep(0.1)
-
- reply = Reply(ReplyType.VOICE, wavFile)
-
- except Exception as e:
- reply = Reply(ReplyType.ERROR, str(e))
- finally:
- return reply
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