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fix: Optimize session expiration

master
Look_World 1 year ago
parent
commit
e1ede58094
1 changed files with 36 additions and 9 deletions
  1. +36
    -9
      common/expired_dict.py

+ 36
- 9
common/expired_dict.py View File

@@ -1,23 +1,50 @@
from datetime import datetime, timedelta
import time
from collections import OrderedDict

class ExpiredDict(dict):

class ExpiredDict(OrderedDict):
def __init__(self, expires_in_seconds):
super().__init__()
# 存储键值对的生存时间
self.expires_in_seconds = expires_in_seconds
# 获取当前时间的函数
self.now = time.monotonic

def __getitem__(self, key):
value, expiry_time = super().__getitem__(key)
if datetime.now() > expiry_time:
# 检查键是否存在
if key not in self:
raise KeyError(key)
# 获取值和过期时间
value, expiry_time = self[key]
# 如果过期时间早于当前时间,删除该键值对并引发 KeyError
if expiry_time is not None and self.now() > expiry_time:
del self[key]
raise KeyError("expired {}".format(key))
self.__setitem__(key, value)
raise KeyError(key)
# 如果存活时间不为 None,更新该键值对的过期时间
if self.expires_in_seconds is not None:
self[key] = value, self.now() + self.expires_in_seconds
# 删除过期的键值对
self._delete_expired_items()
# 返回值
return value

def __setitem__(self, key, value):
expiry_time = datetime.now() + timedelta(seconds=self.expires_in_seconds)
super().__setitem__(key, (value, expiry_time))
# 如果存活时间不为 None,设置该键值对的过期时间
if self.expires_in_seconds is not None:
self[key] = value, self.now() + self.expires_in_seconds
else:
self[key] = value, None
# 删除过期的键值对
self._delete_expired_items()

def get(self, key, default=None):
try:
return self[key]
except KeyError:
return default
return default

def _delete_expired_items(self):
# 遍历所有键值对,删除过期的键值对
for key, (value, expiry_time) in list(self.items()):
if expiry_time is not None and self.now() > expiry_time:
del self[key]

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